In an ap sum of first n terms is 3n 2/2
WebApr 15, 2024 · The sum of the first n terms of an AP is given by Sn = (3n2 – n). Find its (i) nth term, (ii) first term and (iii) common difference. arithmetic progression class-10 1 Answer +1 vote answered Apr 15, 2024 by Nidhi01 (60.1k points) selected Apr 16, 2024 by Vevek01 Best answer Sn = 3n2 – n S1 = 3 (1)2 – 1 = 3 – 1 = 2 S2 = 3 (2)2 – 2 = 12 – 2 = 10 WebAug 9, 2024 · It is an arithmetic progression with first term as 5 and common difference as 6 and 20^(th) term is 119 As sum of n terms of a certain series is given by S_n=2n+3n^2, Sum of 20 terms is 2×20+3×20^2=40+1200=1240. Further, sum of 19 terms is 2×19+3×19^2=38+1083=1121,. Hence 20^(th) term is 1240-1121=119. As sum of 1 term …
In an ap sum of first n terms is 3n 2/2
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WebAn arithmetic progression or arithmetic sequence (AP) is a sequence of numbers such that the difference from any succeeding term to its preceding term remains constant throughout the sequence. The constant difference is called common difference of that arithmetic progression. For instance, the sequence 5, 7, 9, 11, 13, 15, . . . is an arithmetic progression … WebMar 29, 2024 · Misc 3 Let the sum of n, 2n, 3n terms of an A.P. be S1, S2 and S3, respectively . Show that S3 = 3 (S2– S1) We know that Sum of n terms = n/2 [2a + (n – 1)d] i.e. Sn = n/2 [2a + (n – 1)d] where a is the first term & d is the common difference of the A.P. It is given that Sum of n terms = S1 i.e. n/2 [2a+ (n – 1)d] = S1 Also, Sum of 2n ...
WebMar 30, 2024 · There are 2 AP s with different first term and common difference For the first AP Let first term be a common difference be d Sum of n term = Sn = /2 (2a + (n 1)d) & nth term = an = a + (n 1)d Similarly for second AP Let first term = A common difference = D Sn = /2 (2A + (n 1)D) & nth term = An = A + (n 1)D We need to find ratio of 12th term i.e. … WebApr 8, 2024 · Let the sum of n terms be given by Sn. so. Sn = 3n²/2+ 5n/2. S1 = 3(1)²/2 + 5(1)/2 = 3/2+5/2 => 4. so 1st term is 4 say 'a' Now. S2 = 3(2)²/2 + 5(2)/2 = 6+5 => 11. Now …
WebAnswer (1 of 3): Sum of the first n terms, Sₙ= 5n²-2n Let S₄₉ and S₅₀ be the sum of first 49 terms and first 50 terms respectively. Let t₅₀ be the 50 th term. S₅₀= S₄₉+t₅₀ t₅₀= S₅₀-S₄₉ S₄₉ = 5(49)²-2(49) = 11907 S₅₀ = 5(50)²-2(50) = 12400 t₅₀ = …
WebIn an A.P., the sum of first n terms is 3n2 2 + 13 2n. Find its 25th term. Solution n term sum = 3n²/2 + 13n/2 as we know that nth term = (Sum of nth term ) - ( sum of (n-1)th term) …
WebAug 28, 2024 · Let the sum of n terms be given by Sn so Sn = 3n²/2+ 5n/2 S1 = 3 (1)²/2 + 5 (1)/2 = 3/2+5/2 => 4 so 1st term is 4 say 'a' Now S2 = 3 (2)²/2 + 5 (2)/2 = 6+5 => 11 Now a2 … how do i start using youtube tvWebin an AP the sum of first n terms is 3n2/2 + 13n/2 Solution Verified by Toppr Was this answer helpful? 0 0 Similar questions The first term of two APs are equal and the ratios of … how much mush is ardor worthWebMar 27, 2024 · Solution For 10] Find the sum of first ' n ' terms of an AP 2 ,8 ,18 ,32 , 11] If α,β and γ are the zeroes of the polynomial P(x)=x3−6x2−x+30 then fin. The world’s only live instant tutoring platform. Become a tutor About us Student login Tutor login. Login. Student Tutor. Filo instant Ask button for chrome browser. ... how do i start waking up earlyWebAP.CALC: LIM‑7 (EU), LIM‑7.A (LO), LIM‑7.A.1 (EK), LIM‑7.A.2 (EK) Google Classroom. 0 energy points. About About this video Transcript. The partial sum of a sequence gives as the sum of the first n terms in the sequence. If we know the formula for the partial sums of a sequence, we can find a formula for the nth term in the sequence ... how much muscle is attractiveWebJan 8, 2024 · In an AP the sum of first n terms is 3n2/2 + 5n/2 find the 25th term. 9,479 views Jan 7, 2024 253 Dislike Share Save Math Army 81.9K subscribers In an AP the sum of first n... how much muscles does a human haveWebLet the sum of n terms be given by SnsoSn = 3n²/2+5n/2S1 = 3(1)²/2+5(1)/2= 3/2+5/2= 4So 1st term is 4 say aNowS2 = 3(2)²/2+5(2)/2= 6+5= 11Now a2 =S2−a1=> a2 =11−4= 7Now … how do i start watching fateWebJul 21, 2024 · Sn = n 2 (n + 1)(2n + 3) Explanation: Given that n th term of a series is T n = 3n2 + 2n hence, the sum Sn of given series up to first n terms Sn = n ∑ n=1T n = n ∑ n=1(3n2 +2n) = 3 n ∑ n=1n2 + 2 n ∑ n=1n = 3 n 6 (n + 1)(2n + 1) +2 n 2 (n +1) = n 2 (n + 1)(2n + 1 + 2) = n 2 (n + 1)(2n + 3) Answer link how do i start visiting the gym