WebbThe smallest 4 digit number divisible by 24,15 and 36 is a) 1000 b) 1208 c) 1800 d) 1080 Webb22 apr. 2024 · For this number to be divisible by 24, 15 and 36, Required number must be divisible by the LCM of 24, 15 and 36 i.e., by 360. Now on dividing six digit greatest …
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Webb12 apr. 2024 · In the first part of the question, we have to find the greatest number of 5 digits which is exactly divisible by 12, 15 and 36. For that, we will find the L.C.M of these numbers. And then we will divide the greatest 5 digit number which is 99999 by the L.C.M obtained. We will subtract the remainder from the number 99999. WebbQuestion From - NCERT Maths Class 6 Chapter 3 EXERCISE 3.7 Question – 9 PLAYING WITH NUMBERS CBSE, RBSE, UP, MP, BIHAR BOARDQUESTION TEXT:-Find the smallest ...
Webb22 apr. 2024 · For this number to be divisible by 24, 15 and 36, Required number must be divisible by the LCM of 24, 15 and 36 i.e., by 360. Now on dividing six digit greatest number by LCM we get 279 as remainder. Therefore the greatest number of 6 digits exactly divisible by 24, 15 and 36 = Six digit greatest number – remainder = 999999 – 279 = … Webb9 mars 2024 · the smallest 4 digit number divisible by 24,15 and 36 is#lcm #question #maths .Basic Mathematics By KclAcademy Maths Questions Solutions LCM by …
Webb30 mars 2024 · Let’s first find smallest number divisible by 18, 24, 32 Smallest number divisible by 18, 24, 32 = LCM of 18, 24, 32 LCM of 18, 24, 32 LCM = 2 × 2 × 2 × 2 × 2 × 3 × 3 = 288 ∴ 288 is the smallest number divisible by 18, 24, 32 Now, We need to find smallest 4-digit number divisible by 18, 24, 32 Smallest 4 digit number = 1000 we divide 1000 by … WebbYou will receive whole number answers for all of the division. Least common multiple of 15 ( = 3 × 5), 24 ( = 2 3 × 3), 36 ( = 2 2 × 3 2) is the combination of all the biggest prime …
Webb26 juni 2016 · 24 - 19 = 5. 32 - 27 = 5. 31 - 31 = 5. The difference between divisors and reminders is the same in all. According to the question, we have. The LCM of (24, 32 and 36) = 288. Now, The smallest number = LCM - 5. ⇒ 288 - 5. ⇒ 283. ∴ The smallest number is 283, divisible by 24, 32 and 36 and leaves the remainder 19, 27 and 31 respectively.
Webb27 aug. 2024 · 24 = 23 × 3. 36 = 22 × 32. LCM = product of greatest power of each prime factor involved in the numbers = 23 × 32 × 5 = 360. Now, the greatest four digit number … bioplex 2200 package insertWebb21 maj 2024 · Find the smallest 6 digit number exactly divisible by 15 ,24 & 36 - 9916432. nanofficial9 nanofficial9 21.05.2024 Math ... siddhi5589 siddhi5589 The lcm of 15,24,36 is 360.10080 is the smallest 6 digit number that is exactly divisible by 15,24,36. Could you explain in detail Advertisement Advertisement rajeshkumar97 ... bioplex2200 操作手册Webb1 okt. 2024 · As Stuart has very clearly explained above, to be divisible by 16, 24, 36 and 54, the number should be divisible by 2 4 and 3 3 so the number should be a multiple of 432. Out of the given options, lets eliminate 10320 and 10032 right away because they are not even divisible by 9, forget about by 27. biople organic lifeWebbSolution: We will be using the concept of LCM (Least Common Multiple) to solve this. We know that the smallest 4-digit number is 1000. Hence,the LCM of 18, 24 and 32 is calculated as shown below, Therefore, LCM of 18, 24 and 32 = 2 × 2 × 2 × 2 × 2 × 3 × 3 = 288. Thus, we have 288 as the smallest number, which is exactly divisible by 18 ... dairy and gluten free rollsWebbThe smallest 4 digit number divisible by 24,15 and 36 is a) 1000 b) 1208 c) 1800 d)1080 12. The largest number which exactly divides 280 and 1245 leaving remainders 4 and 3respectively is… a) 36 b) 54 c) 138 d) 72 13. The ratio of LCM and HCF of the least composite and the least prime numbers is a) 1:2 b) 2:1 c) 1:1 d) 1:3 14. bioplex 200 system principleWebb6 juni 2024 · Real numbers, Ch... Find the greatest 4 digit number exactly divisible by 24, 15, 36.and the HCF of two numbers is 16 and their product is 3072. Find their LCM. dairy and lectinsWebb10 okt. 2024 · So, LCM of 18, 24 and 36 is 72. But we want the least 4 digit number, which is exactly divisible by 18, 24 and 36. Smallest 4 digit number = 1000. Now, 1000 = (13 $\times$ 72) + 64. Next higher quotient is 14. So, the required number = 14 $\times$ 72 = 1008. Hence, the required number is 1008, which is exactly divisible by 18, 24 and 36. bioplex 200 instructions